2[5(w+3)-w+1]=3(1+w)

Solution for 2[5(w+3)-w+1]=3(1+w) equation:

Simplifying
2[5(w + 3) + -1w + 1] = 3(1 + w)

Reorder the terms:
2[5(3 + w) + -1w + 1] = 3(1 + w)
2[(3 * 5 + w * 5) + -1w + 1] = 3(1 + w)
2[(15 + 5w) + -1w + 1] = 3(1 + w)

Reorder the terms:
2[15 + 1 + 5w + -1w] = 3(1 + w)

Combine like terms: 15 + 1 = 16
2[16 + 5w + -1w] = 3(1 + w)

Combine like terms: 5w + -1w = 4w
2[16 + 4w] = 3(1 + w)
[16 * 2 + 4w * 2] = 3(1 + w)
[32 + 8w] = 3(1 + w)
32 + 8w = (1 * 3 + w * 3)
32 + 8w = (3 + 3w)

Solving
32 + 8w = 3 + 3w

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '-3w' to each side of the equation.
32 + 8w + -3w = 3 + 3w + -3w

Combine like terms: 8w + -3w = 5w
32 + 5w = 3 + 3w + -3w

Combine like terms: 3w + -3w = 0
32 + 5w = 3 + 0
32 + 5w = 3

Add '-32' to each side of the equation.
32 + -32 + 5w = 3 + -32

Combine like terms: 32 + -32 = 0
0 + 5w = 3 + -32
5w = 3 + -32

Combine like terms: 3 + -32 = -29
5w = -29

Divide each side by '5'.
w = -5.8

Simplifying
w = -5.8